SOLUTION: two-column proof
Given: AD is a diameter of ⊙ O;
Dc is tangent to ⊙ O at D.
Prove: ∆ABD ~ ∆ADC
(link to image)
https://photos.google.com/share/AF1QipP8NZbitIdE4if7
Algebra ->
Test
-> SOLUTION: two-column proof
Given: AD is a diameter of ⊙ O;
Dc is tangent to ⊙ O at D.
Prove: ∆ABD ~ ∆ADC
(link to image)
https://photos.google.com/share/AF1QipP8NZbitIdE4if7
Log On
Question 1155104: two-column proof
Given: AD is a diameter of ⊙ O;
Dc is tangent to ⊙ O at D.
Prove: ∆ABD ~ ∆ADC
(link to image)
https://photos.google.com/share/AF1QipP8NZbitIdE4if7gv7lYYeUYvKSWEISM6Qgmxd2lzXcd4Ch0c2RSDOxHLLT5-f7MA/photo/AF1QipNXVz3UAGa3sqxTDM5NKDI9-Vy_ev9eEbUQadKe?key=dVg4TjFJTEV6OWE2clkxYl8wT25OTFRpUW92UWpB
You can put this solution on YOUR website!
In triangle ABD & ADC
ABD is congruent to angle ADC Both right angles
(In ABD tangent perpendicular to radius
ADC angle in a semi circle)
angle A is common in both triangles
Therefore ∆ABD ~ ∆ADC ( AA test of similarity)
