SOLUTION: (a) The number n - 4, n + 2, 3n + 1 are in geometrical progression. Find the two possible values of the common ratio.

Algebra.Com
Question 1153560: (a) The number n - 4, n + 2, 3n + 1 are in geometrical progression. Find the two possible values of the common ratio.

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
You could start like this:


.
.
.

Answer by ikleyn(52784)   (Show Source): You can put this solution on YOUR website!
.

For the full solution, see the link

https://www.algebra.com/algebra/homework/playground/test.faq.question.1153562.html

https://www.algebra.com/algebra/homework/playground/test.faq.question.1153562.html


Also, keep in mind that in English

            THERE  IS  NO  SUCH  a term  "geometrical progression".

            There is the term  "geometric progression",  instead.



RELATED QUESTIONS

The number n - 4, n + 2, 3n + 1 are in geometrical progression. Find the two possible... (answered by MathLover1,ikleyn,MathTherapy)
The numbers n-4, n+2, 3n+1 are in geometrical progression. Find the two possible values... (answered by amarjeeth123)
The sum of the n terms of two arithmetic progression are in the ratio (3n+8):(7n+15).... (answered by ikleyn)
The nth term of a geometric progression is 9(-2/3)^n. Find the first term and the common (answered by ikleyn)
if k+1,2k-1, 3k+1,are three consecutive terms of a geometric progression, find the... (answered by ikleyn)
In a geometrical progression the sum of the 2nd and the 3rd terms is 6 and the sum of the (answered by KMST)
The sum of the second and third terms of a geometric progression is six times the fourth... (answered by ikleyn)
the sum to infinity of a geometric progression is twice the sum of the first two terms.... (answered by stanbon,ramkikk66)
The first term of an arithmetic progression is 12 and the sum of the first 16 terms is... (answered by greenestamps)