SOLUTION: Given 2^m × (1/8)^n = 128 and 4^m ÷ 2^(-4n) = 1/6, find the value of (m-n).

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Question 1144759: Given 2^m × (1/8)^n = 128 and 4^m ÷ 2^(-4n) = 1/6, find the value of (m-n).
Found 2 solutions by Edwin McCravy, MathTherapy:
Answer by Edwin McCravy(20054)   (Show Source): You can put this solution on YOUR website!
















By substitution:





Multiply both sides by 2







Take natural logs of both sides:





Divide both sides by ln(2)





Multiply both sides by 1/10







But you don't want m or n, you want m-n







Edwin
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Given 2^m × (1/8)^n = 128 and 4^m ÷ 2^(-4n) = 1/6, find the value of (m-n). 
I believe you did post this after: test/1144760: Given 2^m × (1/8)^n = 128 and 4^m ÷ 2^(-4n) = 1/16, find the value of (m-n).

If I'm correct, why didn't you DELETE the former?

Why did you allow someone to solve the original problem: "test/1144759," when it contained an error, as itw's SUPPOSED to be: 

, instead of: ?

BTW,  

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