(a)  The median from vertex J goes through the point J= (1,4)  and the midpoint of KL, which (midpoint) is (0,-2.5).


     So, the slope of this median is  m =  =  = 6.5.


     Therefore, the equation of this median from vertex J is


         y-4 = 6.5*(x-1).


     You can transform this equation to any equivalent form you want / (you need).




(b)  To solve (b),  do it similarly, having my solution to (a) as a TEMPLATE before your eyes.




(c)  The segment JL has the slope


     m =  =  = -4.


    Hence, the perpendicular line to segment JL has the slope of 0.25.


    The midpoint of the segment JL is the point (2,0).


    Therefore, the equation of the right bisector to side JL is


        y = 0.25*(x-2).


     You can transform this equation to any equivalent form you want / (you need).