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Let "a" be the number of copies the machine A makes per minute,
"b" be the number of copies the machine B makes per minute, and
"c" be the number of copies the machine C makes per minute.
From the condition, we have these equations
a + b = 100 (1)
a + c = 140 (2)
a + b + c = 180 (3)
To solve the system, first subtract equation (1) from equation (3). You will get
c = 180 - 100 = 80.
Next step subtract equation (2) from equation (3). You will get
b = 180 - 140 = 40.
To find "a", substitute b= 40 into equation (1):
a + 40 = 100, which implies a = 100 - 40 = 60.
ANSWER. a= 60; b= 40; c= 80.
Solved.
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The problem also can be solved mentally.
To see many other similar solved problems, look into the lessons
- The tricks to solve some word problems with three and more unknowns using mental math
in this site.