The larger and smaller containers are similar, and their linear measurements are in the ratio 4:1 - - so their volumes are in he ratio 4^3 : 1^1, or 64:1. If x cm^3 is the volume of the smaller, then 64x cm^3 is the volume of the larger. The rest of the condition is not clear to me, but these HINTS are enough for you to complete the solution on your own.