SOLUTION: Becky and Delia, living 450 meters apart, leave their homes on a pedicab and travel toward each other. If Becky averages 3 meters per minute more than Delia and they meet after 30

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Question 1133384: Becky and Delia, living 450 meters apart, leave their homes on a pedicab and travel toward each other. If Becky averages 3 meters per minute more than Delia and they meet after 30 minutes, then find their rates of cycling.


Found 2 solutions by Boreal, josmiceli:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
x m/min for slower
x+3 m/minfor faster
30 minutes for 450 meters is 15 meters/min
combined speed is 2x+3 m/min
2x+3=15
2x=12
x=6 m/min for Delia
x+3=9 m/min for Becky

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Let = the speed of the slower bike in m/min
= the speed of the faster bike in m/min
-----------------------
Since their speed will add, you can view this as
one of them moving at the sum of their speeds
and the other one standing still, so I can say:




m/min
and
m/min
------------------------------
Their speeds are 6 m/min and 9 m/min
---------------------------------------------
check:


and


and

m
OK

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