SOLUTION: Solve for 0° ≤ θ ≤ 360°: 2cosēθ - 3sin2θ - 2 = 0 Note: It's 3sin2θ and not 3sinēθ

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Question 1132138: Solve for 0° ≤ θ ≤ 360°:
2cosēθ - 3sin2θ - 2 = 0
Note:
It's 3sin2θ and not 3sinēθ

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Solve for ° ≤ °:















solutions:
if




=> , element
for ° ≤ θ ≤ °=>
°


or, if








general solution for is:

° and °

°

°

°

°



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