SOLUTION: Solve for 0° ≤ θ ≤ 360°: 2cosēθ - 3sin2θ - 2 = 0

Algebra.Com
Question 1132133: Solve for 0° ≤ θ ≤ 360°:
2cosēθ - 3sin2θ - 2 = 0

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Solve for ° ≤ °:







° and °


RELATED QUESTIONS

Solve for 0° ≤ θ ≤ 360°: 2cosēθ - 3sin2θ - 2 = 0 Note:... (answered by MathLover1)
Solve the following equations for 0 ≤ θ ≤ 180 degrees. 6.a. sin^2... (answered by Theo)
if 0≤θ<360°, solve the equation: sec^2(2θ)+... (answered by stanbon)
Solve the equation for 0 ≤ θ ≤ 2π. cosθ - sinθ = 0 (answered by Fombitz)
0° ≤ θ < 360° 2sin(θ)-sqrt3=0 solve for... (answered by MathLover1,ikleyn)
solve exactly over 0 ° ≤ θ < 360° : 4cos^2θ - 4sinθ =5 (answered by ikleyn)
What values for theta( 0 ≤ theta ≤ 2pi) satisfy the equations? 1.4cos... (answered by ikleyn)
Solve the following equation given that 0° ≤ θ < 360° : sin θ cos... (answered by ikleyn)
Please help me Solve the following equation for x, if 0 ≤ x ≤ 2π... (answered by lwsshak3,josgarithmetic)