SOLUTION: Solve for 0° ≤ θ ≤ 360°:
2cosēθ - 3sin2θ - 2 = 0
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Question 1132133: Solve for 0° ≤ θ ≤ 360°:
2cosēθ - 3sin2θ - 2 = 0
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Solve for ° ≤ ≤ °:
° and °
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