SOLUTION: Prove that the area of the minor segment cut off from a circle of radius r cm by a chord c cm from the centre of the circle is given by (1/2)[2π{cos^(-1)(c/r)}*r²/180° - 2c(r

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Question 1131926: Prove that the area of the minor segment cut off from a circle of radius r cm by a chord c cm from the centre of the circle is given by
(1/2)[2π{cos^(-1)(c/r)}*r²/180° - 2c(r²-c²)^½]

Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
duplicate
Answer by Edwin McCravy(20062)   (Show Source): You can put this solution on YOUR website!




            

That's equivalent to what you have above since

 and the inverse cosine is multiplied by  
to change degrees to radians, for apparently degrees are assumed 
by the author of this problem.  If radians were assumed for the 
inverse cosine, we would not use the factor .

Edwin

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