SOLUTION: A shot putter throws the shot with an initial speed of 14 m/s at a 40 degrees angle to the horizontal. Calculate the horizontal distance traveled by the shot?

Question 1129537: A shot putter throws the shot with an initial speed of 14 m/s at a 40 degrees angle to the horizontal. Calculate the horizontal distance traveled by the shot?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A shot putter throws the shot with an initial speed of 14 m/s at a 40 degrees angle to the horizontal. Calculate the horizontal distance traveled by the shot?
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The vertical speed at launch is 14*sin(40) m/sec =~ 8.999 m/sec
Using 9.8 m/sec/sec for Earth's gravity:
h(t) = -4.9t^2 + vo*t + h where vo is the launch speed (8.999) and h is the launch (which was not given)
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h(t) = -4.9t^2 + 8.999t =0 at impact
Solve for t (Ignore t = 0)
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The horizontal speed is 14*cos(40) =~ 10.725 m/sec
Horizontal distance = 10.725t
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The height at launch should be taken into account.

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