SOLUTION: A store sells 200 burgers daily at $4.59 each. Every 10 cents price increase reduces sales by 3 burgers. Find the maximum income from the burger sales and the price at which they s

Question 1120669: A store sells 200 burgers daily at $4.59 each. Every 10 cents price increase reduces sales by 3 burgers. Find the maximum income from the burger sales and the price at which they should be sold.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Income is currently $918; let x=number sold
(4.59+0.10x)*(200-3x)=918-13.77x+20x-0.3x^2=-0.3x^2+6.23x+918.
new price* #sold
the vertex is at -b/2a or -6.23/-0.6=10.4 burgers.
10 will yield slightly greater sales than 11
for 10: 5.59*170=$950.30
for 11: 5.69*167=$$950.23

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