SOLUTION: A husband is 3years older than his wife. the sum of their ages is 73 years.calculate the difference between the square of their ages

Question 1117447: A husband is 3years older than his wife. the sum of their ages is 73 years.calculate the difference between the square of their ages

Found 2 solutions by Alan3354, math_helper:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
H - W = 3
H + W = 73
--------------------- Add

Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
h - w = 3
h + w = 73
The difference between the square of their ages is (h-w)(h+w) = 3*73 =
(yrs^2 units).

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