SOLUTION: Three WHOLE numbers are each rounded to the
nearest 10
The sum of the rounded numbers is 70
Work out the MAXIMUM possible sum for the
original three numbers.
Algebra.Com
Question 1117406: Three WHOLE numbers are each rounded to the
nearest 10
The sum of the rounded numbers is 70
Work out the MAXIMUM possible sum for the
original three numbers.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The largest whole number that can be rounded DOWN to the nearest 10 is a whole number with a units digit of 4. So if you have 3 whole numbers that end in a 4 and round them to the nearest 10 you lose 4 for each of the numbers for a total of 12 for the three addends. So if the first rounded number is 
, the second is 
, and the third is 
, the largest each of these numbers could be BEFORE rounding would be 
, 
, and 
.
Since we are given that 
, it should be obvious that 
John
My calculator said it, I believe it, that settles it
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