SOLUTION: A special rubber ball is dropped from the top of a building 81m high. if after the falling it bounces back to two-thirds of the previous bouncing height, then
how high will it bou
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Question 1090862: A special rubber ball is dropped from the top of a building 81m high. if after the falling it bounces back to two-thirds of the previous bouncing height, then
how high will it bounce the 5th time?
what is the total distance it has covered the 6th time it touch the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A special rubber ball is dropped from the top of a building 81m high. if after the falling it bounces back to two-thirds of the previous bouncing height, then
how high will it bounce the 5th time?
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81 m *(2/3)^5 = 81*32/243 = 32/3 meters
============================
what is the total distance it has covered the 6th time it touch the ground?
Find the height of each bounce.
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0th - 81 meters (when released)
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bounces:
1st - 81*2/3 = 54 up, 54 down
2nd - 54*2/3 = 36
3rd - 36*2/3 = 24
4th - 24*2/3 = 16
5th - 16*2/3 = 32/3
---
Add 1st thru 5th = 422/3 meters up and down
Times 2 = 844/3 meters traveled.
+ the 81 meter drop --> 1087/3 meters
=~ 362.333 meters
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