SOLUTION: A particle moves in a straight line so that its distance, s m, from a fixed point A on the line is given by s=2t^2-4t+9, for t less than or equal to 3, where t is the time in secon
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Question 1081862: A particle moves in a straight line so that its distance, s m, from a fixed point A on the line is given by s=2t^2-4t+9, for t less than or equal to 3, where t is the time in seconds after passing through a point B on the line.
(a) the total distance travelled by the particle in the period of t=0 to t=3. Ans=10m
(b) At t=3, the acceleration of the particle is changed to (t − 8)m/s2 , the instantaneous velocity remaining unchanged. Find the next value of t at which the particle comes to instantaneous rest. Ans= 5s
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
a)
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Looking at the graph, the particle travels from 9 to 7 in the 1st second, from 7 to 9 in the 2nd second and from 9 to 15 in the 3rd second.
So it traveled,
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b) Find the instantaneous velocity when ,
So then integrate the new acceleration to get the new velocity,
When ,,
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for
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Graphing this and looking for the next crossing of the x-axis,
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You could also factor,
and
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