SOLUTION: sqrt 8 x sin theta = 2, where theta (- pi;2 pi)
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Question 1080676
:
sqrt 8 x sin theta = 2, where theta (- pi;2 pi)
Answer by
Alan3354(69443)
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sqrt 8 x sin theta = 2, where theta (- pi;2 pi)
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2sqrt(2)*sin(t) = 2
sin(t) = 1/sqrt(2) = sqrt(2)/2
t = 45, 135 degs
t = pi/4, 3pi/4
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"where theta (- pi;2 pi)" is not clear.