SOLUTION: Find the equation of a Parabola with Vertex: (2,-1) and directrix: x= -2 (y-1)� = 16(x-2) (y-1) = 16(x+2)� (y+1) = 16(x-2)� (y+1)� = 16(x-2)

SOLUTION: Find the equation of a Parabola with Vertex: (2,-1) and directrix: x= -2 (y-1)� = 16(x-2) (y-1) = 16(x+2)� (y+1) = 16(x-2)� (y+1)� = 16(x-2)

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Question 1078986: Find the equation of a Parabola with Vertex: (2,-1) and directrix: x= -2
(y-1)� = 16(x-2)
(y-1) = 16(x+2)�
(y+1) = 16(x-2)�
(y+1)� = 16(x-2)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The vertex would give a (y+1), (x-2) picture, and the directrix at x=-2 would mean a parabola opening horizontally, so the y would be squared, not the x.
(y+1)^2-16(x-2).
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