SOLUTION: The standard form equation of a circle with center at (-4,2) and radius 4 is A.) (x-4)� + (y+2)� = 16 B.) (x-4)� + (y+2)� = 4 C.) (x+4)� + (y-2)� = 16 D.) (x+4)� + (y-2)� = 4

Question 1078984: The standard form equation of a circle with center at (-4,2) and radius 4 is
A.) (x-4)� + (y+2)� = 16
B.) (x-4)� + (y+2)� = 4
C.) (x+4)� + (y-2)� = 16
D.) (x+4)� + (y-2)� = 4
Found 2 solutions by josgarithmetic, Boreal:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
(C)
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
C. This will be (x+4)^2+(y-2)^2=16
reverse the signs of the coordinates and put by the x and y, square the radius.
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