SOLUTION: Please help me with this
Given, z₁=6(cos150°+isin150°), z₂=4(cos60°+isin60°)
The value of z₁*z₂ would be either
A.) 6(cos210 + i sin210)
B.) 4(cos210 -
Algebra.Com
Question 1072747: Please help me with this
Given, z₁=6(cos150°+isin150°), z₂=4(cos60°+isin60°)
The value of z₁*z₂ would be either
A.) 6(cos210 + i sin210)
B.) 4(cos210 - i sin210)
C.) 24(cos210 + i sin210)
D.) 24(cos210 - i sin210)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
duplicate
RELATED QUESTIONS
Please help me with this.
Given, z₁=6(cos150°+isin150°),... (answered by ikleyn,Alan3354)
If Given, z₁=6(cos150°+isin150°), z₂=4(cos60°+isin60°)
The value of... (answered by Alan3354)
If Given, z₁=6(cos150°+isin150°), z₂=4(cos60°+isin60°)
The value of... (answered by Alan3354,ikleyn)
If Given, z₁=6(cos150°+isin150°), z₂=4(cos60°+isin60°)
The value of... (answered by estron7)
If Given, z₁=6(cos150°+isin150°), z₂=4(cos60°+isin60°)
The value of... (answered by ikleyn)
Is the right answer to this, D? Given, z₁=6(cos150° + isin150°), z₂ =... (answered by Alan3354)
Is the right answer to this, D? Given, z₁=6(cos150° + isin150°), z₂ =... (answered by Fombitz)
If Given, z₁=6(cos150° + isin150°), z₂ = 4(cos60° + isin70°)
Then the value (answered by Alan3354)
2x₁+3x₂ =-2
x₁+2x₂+3x₃=0
-x₂-5x₃=1... (answered by Fombitz,Newb)