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A takes 30 minutes to reach a shop from his residence. B takes 20 minutes to reach the same shop from same residence.
one day A departed to shop at 8a.m. if B departed 5 minutes later. at what time B passes A?
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Let D be the distance from the residence to the shop.
A has the speed units per minute, while B has the speed units per minute.
Let "t" be the time counted from 8:05 am.
The distance for B is .
The distance for A is .
The equation for the time is
= .
Multiply everything by 60/D. You will get
3t = 5*2 + 2t, or
3t - 2t = 10,
t = 10.
Answer. B passes A at 8:15 am.
Solved.