SOLUTION: Given Sin(A) = {{{ 3/5 }}} and Cos(B) = {{{ 8/17 }}} in Quadrant I, find Tan(A+B). A.) {{{ 0.8 }}} B.) {{{ -1.72 }}} C.) {{{ -4.21 }}} D.) {{{ -6.46 }}} Thanks.

Question 1064670: Given Sin(A) = and Cos(B) = in Quadrant I, find Tan(A+B).
A.)
B.)
C.)
D.)
Thanks.
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
tan(A+B) = (tan(A) + tan(B)) / (1 - tan(A)tan(B))
:
sin^-1 (3/5) = 36.8699
:
cos^-1 (8/17) = 61.9275
:
tan(A) = tan(36.8699) = 0.75
:
tan(B) = tan(61.9275) = 1.875
:
********************************************************
tan(A+B) = (0.75 + 1.875) / (1-(0.75 * 1.875)) = -6.4615
:
Answer is D.)
********************************************************
:
Note we could have calculated tan(36.8699 + 61.9275) which is
equal to our calculation above
:

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