SOLUTION: H(x) = -5x^2 + 2x h(-5) + h(2) I do not know how to do this

Algebra.Com
Question 1060548: H(x) = -5x^2 + 2x
h(-5) + h(2)
I do not know how to do this

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
H(x) = -5x^2 + 2x
h(-5)
-------
Wherever you see x, sub -5
h(-5) = -5*(-5)^2 + 2*(-5) = -125 - 10 = -135
===========
h(2)
Do the same with 2, then add them.
==================
It's a lot easier than it looks.

RELATED QUESTIONS

how do you evaluate this function? h(x)=5/2x+x^2 find... (answered by jim_thompson5910)
how do i slove this problem h(x)= x^2+4x-5 ; h(x)>0 (answered by richwmiller)
How would I do this problem? Compute and simplify {{{ (F(x+h)-F(x))/h }}} (assume H is (answered by psbhowmick)
i dont know what algebra is this but i do noy understand it h(x)=2x+5;Calcula h(-10) (answered by ikleyn)
How do i solve: h(x)=3x^2+5 if... (answered by jim_thompson5910)
Given functions f(x)=3x-4, g(x)=2x^2-7, h(x)=square root of x+5 Find (f o g)(x)= Find (answered by scott8148)
Let g(x) = 2x and h(x) = {{{ x^2 + 4 }}}. Question: (g o h)(-2) I will like to know... (answered by josgarithmetic)
Please help I need to know do these Quadriac Equations have a solution or not. And how to (answered by stanbon)
how do you graph h(x)= 4/5x+2? (answered by Menjax)