SOLUTION: A radiator contains 10 quarts of fluid, 10% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 25% antifreeze? (R

Question 1052341: A radiator contains 10 quarts of fluid, 10% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 25% antifreeze? (Round your answer to two decimal places.)
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Right now, you have 10 qts. of fluid, of which 10% is anti-freeze. Let n be the amount of pure anti-freeze to be added. Then:
.1(10)-.1n+n=.25(10)
1+.9n=2.5
.9n=1.5
n=1.67 qts. need to be replaced with pure anti-freeze to achieve the desired mix. ☺☺☺☺
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