SOLUTION: An object is traveling at a constant velocity of 25 m/s when it experiences a constant acceleration of 1.5 m/s^2 for a time of 38 s. What will its velocity be after that accelerati
Algebra.Com
Question 1051677: An object is traveling at a constant velocity of 25 m/s when it experiences a constant acceleration of 1.5 m/s^2 for a time of 38 s. What will its velocity be after that acceleration?
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.
An object is traveling at a constant velocity of 25 m/s when it experiences a constant acceleration of 1.5 m/s^2 for a time of 38 s.
What will its velocity be after that acceleration?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
V = = 25 + 1.5*38.
where is the initial velocity of 25 m/s and "a" is the given acceleration of 1.5 m/s^2.
"t" is the time, 38 seconds in this case.
Use your calculator. In other words, calculate it on your own.
RELATED QUESTIONS
can someone please help me with this problem
The distance d traveled by an object... (answered by Alan3354)
A ball is traveling at a constant velocity of 50 m/s and has been traveling for over 2... (answered by Alan3354)
a car traveling at 3.0 m/s has a constant acceleration of 4.0 m/s^2 after 2.0 seconds,... (answered by Fombitz,Kasandra24)
The height of an object above the ground at time t is given by
s(t) = -0.5gt^2 +ut... (answered by ikleyn)
When a constant force is applied to an object, the acceleration of the object varies... (answered by josgarithmetic)
When a constant force is applied to an object, the acceleration of the object varies... (answered by Alan3354)
An unidentified object moves along the s-axis, with displacement s = s(t) (meters),... (answered by Jk22)
An object initially at rest experiences an acceleration of +9.8m/s^2. How much time will... (answered by ikleyn)
The acceleration of a point is given by a=4−t^2 m/s^2. Write an equation for the... (answered by Fombitz)