SOLUTION: Binomial theorem: Find the term independent of x in the expansion of (1+x^6)(x^-2-3x)^9 where (x^-2-3x)^9 = 10206x^-6

Question 1050295: Binomial theorem:
Find the term independent of x in the expansion of (1+x^6)(x^-2-3x)^9 where (x^-2-3x)^9 = 10206x^-6
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the term independent of x in the expansion of (1+x^6)(x^-2-3x)^9 where (x^-2-3x)^9 = 10206x^-6
----------
(1+x^6)(10206x^-6) = 10206x^-6 + 10206
-----
Ans: 10206
------------
Cheers,
Stan H.
----------
RELATED QUESTIONS
find the term independent of x in the expansion... (answered by stanbon)

Find the sixth term in the expansion of {{{ (3x^2 - 1/x)^9... (answered by ikleyn,MathTherapy)

find the independent term of x in the expansion of... (answered by Edwin McCravy)

Find the term that is independent of x in the expansion of... (answered by MathLover1,greenestamps)

Find the term that is independent of x in the expansion of {{{ (2 + 3/x^2) (x - 2/x)^6... (answered by KMST)

Find the fifth term of the expansion of (x +3)^9 I worked it out to =10206x^5. Am I... (answered by user_dude2008)

Hi, can help me solve this? Thankss~ (a) Find the term that is independent of x in the... (answered by ikleyn)

Calculate the term independent of x in the binomial expansion of (x-1/2x^5)^18 (answered by KMST,MathTherapy)

FInd the x^2 term in the expansion of (2 +3x)^2(4x... (answered by Boreal,greenestamps)