SOLUTION: A container is being filled with water. After t seconds the depth of water, x cm, in the container is increasing at the rate of 1.44tcm/s.
Given that the container is empty when t
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-> SOLUTION: A container is being filled with water. After t seconds the depth of water, x cm, in the container is increasing at the rate of 1.44tcm/s.
Given that the container is empty when t
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Question 1047165: A container is being filled with water. After t seconds the depth of water, x cm, in the container is increasing at the rate of 1.44tcm/s.
Given that the container is empty when t=0, use calculus to find
the approx increase in x as t increases from 4 to 4.1. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A container is being filled with water. After t seconds the depth of water, x cm, in the container is increasing at the rate of 1.44tcm/s.
Given that the container is empty when t=0, use calculus to find
the approx increase in x as t increases from 4 to 4.1.
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If the rate is 1.44t cm/sec:
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Level at 4.1 sec = 1.44*4.1*4.1
Level at 4 sec = 1.44*4*4
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Avg increase is the difference in level divided by 0.1 in cm/sec
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No need for calculus.
