SOLUTION: A container is being filled with water. After t seconds the depth of water, x cm, in the container is increasing at the rate of 1.44tcm/s. Given that the container is empty when t

Question 1047165: A container is being filled with water. After t seconds the depth of water, x cm, in the container is increasing at the rate of 1.44tcm/s.
Given that the container is empty when t=0, use calculus to find
the approx increase in x as t increases from 4 to 4.1.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A container is being filled with water. After t seconds the depth of water, x cm, in the container is increasing at the rate of 1.44tcm/s.
Given that the container is empty when t=0, use calculus to find
the approx increase in x as t increases from 4 to 4.1.
--------------
If the rate is 1.44t cm/sec:
---
Level at 4.1 sec = 1.44*4.1*4.1
Level at 4 sec = 1.44*4*4
---
Avg increase is the difference in level divided by 0.1 in cm/sec
==========
No need for calculus.
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