SOLUTION: 2^x 3^y 5^z=2000 where x,y,z are integers. Find the value of 2x+3y+5z

Question 1044643: 2^x 3^y 5^z=2000 where x,y,z are integers. Find the value of 2x+3y+5z
Answer by ikleyn(52790) (Show Source): You can put this solution on YOUR website!
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2^x 3^y 5^z=2000 where x,y,z are integers. Find the value of 2x+3y+5z
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1.  2000 = 2^4*3^0*5^3.

2.  If   = 2000, then x = 4,  y = 0,  z = 3.

3.  Having this, calculate 2x + 3y + 5z.

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