SOLUTION: The curve y=ax^3+2x^2+a^2x+b has a minimum point at (-1,0). Find a and b.
Algebra.Com
Question 1044048: The curve y=ax^3+2x^2+a^2x+b has a minimum point at (-1,0). Find a and b.
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
----Must be for .
Let x=-1;
, from the derivative being 0 when x is -1;
ALSO from the original equation,
so the problem gives the system of equations,
Solve this system (first, for "a", and then for b).
-
First equation of the system is factorable.
and the description gave, ",... has a minimum point at (-1,0)".
Either the equation becomes or . Do you believe that the second-derivative might give further information about x at -1 being minimum or maximum?
RELATED QUESTIONS
The curve y=ax^3+2x^2+a^2x+b has a minimum point at (-1,0). Find a and b.
But i found (answered by josgarithmetic)
The curve y=ax^3+2x^2+a^2x+b has a minimum point at (-1,0). Find a and b.
So, how do... (answered by josgarithmetic)
The function y = ax^3 + bx^2 + cx + d has a maximum turning point at (−2, 27) and a... (answered by Solver92311)
The tangent to the curve y = 2x^2 + ax + b at the point (-2,11) is perpendicular to the... (answered by math_tutor2020)
The tangent to the curve y = ax^3 + bx at the point (1,3) crosses the y-axis at... (answered by Boreal)
Hi can you plz help me with this qs? I didn't know under which section to post it so im... (answered by greenestamps)
The graph of y = 2x^3 + ax^2 + b has a stationary point (-3,19) . Find the value of a and (answered by greenestamps)
a) show that the equation 0.25x squared - 0.7+ 1.5 =0 does not have any real roots.
b) (answered by malglu)
A line through(2 , 1)meets the curve x squared - 2x - y=3 at A(-2 , 5) and at B.Find the... (answered by lwsshak3,ewatrrr)