SOLUTION: Marine city bus left camp for ghq at 732 am averaging 96mph.another bus left ghq at 1146am averaging 113 mph.if ghq is 5420.8 miles from the camp to the nearest minute at what time

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Question 1043398: Marine city bus left camp for ghq at 732 am averaging 96mph.another bus left ghq at 1146am averaging 113 mph.if ghq is 5420.8 miles from the camp to the nearest minute at what time will the busses pass each other?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
                    RATE        TIME                DISTANCE
Camp to ghq           96         t+(11:46-07:32)     
ghq to Camp          113          t 
Total Consumed                                        5420.8


Total distance that each travels must be the distance between the two locations. Notice higher speed goes with lesser time. Turn the time difference of time points into a time variable expression using t.

4 hours 46-32 minutes
4 hours 14 minutes
4%267%2F30 hours 

                    RATE        TIME                DISTANCE
Camp to ghq           96         t+4&7/30           96(t+4&7/30)
ghq to Camp          113          t                 113*t
Total Consumed                                        5420.8

highlight%2896%28t%2B4%267%2F30%29%2B113t=5420.8%29

Solve that for t.
The slower bus had been moving for 4 hours 14 minutes; and then the faster bus began its travel and did this for t hours. The two buses pass each other t hours AFTER 11:46 - AM seemed to be implied throughout.