SOLUTION: Q: Find the constant k so that the perpendicular bisector of the line segment with end points (k , 0) and (4 , 6) has a slope 0f -3. A) 4 B) -14 C) 6 D) 22 E) 0

Question 1041215: Q: Find the constant k so that the perpendicular bisector of the line segment with end points (k , 0) and (4 , 6) has a slope 0f -3.
A) 4
B) -14
C) 6
D) 22
E) 0
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The perpendicular bisector has a slope of (1/3), the negative reciprocal of -3.
Therefore, (6-0)/(4-k), the slope, must equal (1/3)
cross multiply, and 4-k=(6*3)=18
k=-14, or B. ANSWER
(-14,0) and (4,6) has a slope of 1/3. (the equation of the line is y=(1/3)x+(14/3)
the midpoint is (-5,3), so the equation of the perpendicular bisector is y-3=-3(x+5), or y=-3x-12

Answer by ikleyn(52778) (Show Source): You can put this solution on YOUR website!
.
This my notice goes to the tutor Boreal.

Dear Mr. Boreal!

If you want to make your plots realistic (perpendicular lines etc.),
then keep the sides "aspect ratio" the same for "x" and "y" axis in your plots!

I just fixed it in your last plot.

ikleyn

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