SOLUTION: There are 50 boys and 60 girls in the cafeteria .After x boys and x-5 girls left the cafeteria the probability of selecting a girl becomes 5/7,what is the value of x?
Algebra.Com
Question 1040862: There are 50 boys and 60 girls in the cafeteria .After x boys and x-5 girls left the cafeteria the probability of selecting a girl becomes 5/7,what is the value of x?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
After x boys left, there are 50 - x boys remaining.
After x-5 girls left, there are 60 - (x-5) = 65 - x girls remaining.
==>
<==>
==> 7(65-x) = 5(115-2x), after cross-multiplication.
==> 455 - 7x = 575 - 10x
==> 3x = 120 ==> .
RELATED QUESTIONS
8 There are 50 boys and 60 girls in the cafeteria. After x boys and x – 5 girls have left (answered by math_helper)
girls are occupying exactly 2/5 of the sea in a cafeteria and boys I can find exactly 3/7 (answered by macston)
From a group of boys and girls, 15 girls leave. There are then left two boys for each... (answered by ankor@dixie-net.com)
From a group of boys and girls, 15 girls leave. There are then left two boys for each... (answered by josmiceli)
In the cafeteria, the ratio of the number of girls to boys is 6:7. When 117 girls enter... (answered by josmiceli)
From an original group of boys and girls, twenty girls leave. There are then left two... (answered by josmiceli)
There are 46 boys and girls that attend a play. There are 8 more girls than boys. Let X... (answered by dkppathak)
there are 3 more girls than boys in tom's clas, and the sum of girls and the boys is 41.... (answered by shweta)
There are x boys and y girls in a class (class A). The girls outnumber the boys by 4.... (answered by Boreal)