SOLUTION: Consider a function F(x)= x^3 -x^2 -x -8. If F(u)= -8,how many real values of u are there?

Algebra.Com
Question 1040850: Consider a function F(x)= x^3 -x^2 -x -8. If F(u)= -8,how many real values of u are there?
Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
and F(u) = -8
==>
==> ==>
==> the roots are u = 0, .
==> there are three real values for u.

RELATED QUESTIONS

... (answered by greenestamps)
Consider the polynomial function f(x)=x^4-x^3-x^2-x-2 a) How many zeros does f(x)... (answered by Fombitz)
List all real values of x such that f(x) = 0. If there are no such real x, type DNE. If... (answered by stanbon)
List all real values of x such that f (x) = 0. If there are no such real x, type DNE in (answered by stanbon)
Please can someone help me solve the following. I would really appreciate some help.... (answered by stanbon)
What values are excluded from the domain of the function? (Separate multiple answers with (answered by drk)
Consider the general quadratic function f(x)=a(x-h)^2+k, where a, h, and k are real... (answered by longjonsilver)
Consider the following function: F(x): 1-x x<-1 x... (answered by stanbon)
complete the table if the function f is even x values are -8,-4,4,8 and f(x) are... (answered by jsmallt9)