SOLUTION: Passing through (4,-8) and perpendicular to the line whose equation is x-5y=3
Write an equation for this line in point slope form:
Also
Write and equation for this line in
Algebra.Com
Question 1040715: Passing through (4,-8) and perpendicular to the line whose equation is x-5y=3
Write an equation for this line in point slope form:
Also
Write and equation for this line in slope-intercent form:
Please help
Found 3 solutions by Boreal, josgarithmetic, ikleyn:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The line x-5y=3 may be written as 5y=x-3 or y= (1/5)x-(3/5), slope -intercept form. The slope of the line perpendicular to this line is the negative reciprocal of the coefficient of x. That is the negative reciprocal of (1/5). To find that, flip the fraction and change the sign. It is therefore -5.
point slope form of the line that goes through (4,-8) perpendicular to the line given has slope -5
y-(-8)=-5(x-4)
y+8=5(x-4) That is point-slope form
y=5x-20-8
y=5x-28 That is slope-intercept form.
Graph doesn't show x and y the same interval for each.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The slope for the given line is and any line in the plane perpendicular to it will have slope . Perpendicular lines in a plane have slopes which are negative reciprocals.
Now the question is, what is the equation for a line passing through point (4,-8) and with slope ?
Using the point-slope form of equation, .
Simplify this and solve for y in terms of x.
-------the same line but now in slope-intercept form.
Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
.
If you fix errors in the Boreal solution, then you probably will get the correct answer.
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