SOLUTION: Hello, can you state the possible number of imaginary zeros for these two functions?
1. f(x) = -x³ -x² + 14x - 24
2. f(x) = 2x³ - x² + 16x - 5
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Question 1037022: Hello, can you state the possible number of imaginary zeros for these two functions?
1. f(x) = -x³ -x² + 14x - 24
2. f(x) = 2x³ - x² + 16x - 5
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
For polynomial functions with real coefficients, imaginary zeros come in pairs, so a polynomial function with real coefficients can have 0,2,4, 6,...imaginary zeros.
However, a polynomial with degree 3 cannot have more than 3 zeros,
so these functions can have or imaginary zeros.
Polynomials of odd degree must have at least 1 real zero.
They could have 1, 3, 5, all the way up to their degree.
NOTE:
Each of those functions happens to have exactly 1 real zero.
Some calculus plus calculations (or a graphing calculator) would tell you that.
Since they are cubic (degree=3) polynomials, they must have a total of 3 zeros,
so the other zeros are imaginary.
You are probably not expected to be able to reach that conclusion, though.
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