SOLUTION: The parabola with equation y = 8x � x2 has x-intercepts at 0 and 8. How many units must the parabola be translated down so that the distance between the x-intercepts is 4?

Question 1035188:
The parabola with equation y = 8x � x2 has x-intercepts at 0 and 8. How many units must the parabola be translated down so that the distance between the x-intercepts is 4?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The parabola with equation y = 8x � x^2 has x-intercepts at 0 and 8. How many units must the parabola be translated down so that the distance between the x-intercepts is 4?
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Original parabola DATA:
Axis of symmetry:: x = 4
Vertex:: (4,f(4)):
f(4) = 8*4-4^2 = 16
Vertex:: (4,16)
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You want the x-intercepts to be 4-2 = 2 and 4+2 = 6
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Form::
y = -(x-2)(x-6)
Solve::
y = -(2-2)(2-6)
y = -0(-4) = 0
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So, the new vertex is (2,0)
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Ans:: down from (2,16) to (2,0)
down 16 units
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Cheers,
Stan H.
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