SOLUTION: 3. Find the equation of each tangent of the function f(x) = x3 +x2 +x+1 which is perpendicular to the line 2y + x +5=0. 3.

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Question 1034488: 3. Find the equation of each tangent of the function f(x) = x3 +x2 +x+1 which is perpendicular to the line 2y + x +5=0. 3.
Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
==> f'(x) = .
Now the line 2y + x +5=0 has slope -1/2. Any line perpendicular to it must have slope 2.
We now find points on the graph whose tangents have slope 2.
==> f'(x) = ==>
==> (3x-1)(x+1) = 0 ==> x = 1/3, x = -1.
Now f(1/3) = 40/27, and f(-1) = 0.
==> The two lines are and .
Simplify these equations yourself.

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