SOLUTION: [0,2pi] cos^(2x)+2cos(x)+1=0
Algebra.Com
Question 1031318: [0,2pi] cos^(2x)+2cos(x)+1=0
Answer by ikleyn(52798) (Show Source): You can put this solution on YOUR website!
.
1. Fix your equation.
2. Do you read your post?
RELATED QUESTIONS
1.Solve the equation 2cos x-1=0, 0 (answered by stanbon)
15 cos^2x+2cos x-1=0 [-2,2] (radian mode) (answered by lwsshak3)
Solve the equation for x, on the interval 0 is less than or equal to x and 2pi is greater (answered by Alan3354)
what are all the solutions of 2cos^2(x)-cos(x)-1=0 that lie in the interval [0,... (answered by solver91311)
Solve on the interval [0, 2pi]
2cos*2x=1
(answered by Theo)
Please solve the equation for the interval [ 0, 2pi ]:
{{{2cos^2(2x)-cos(2x)=0}}}... (answered by ikleyn)
cos^2(x)+2cos(x)+1=0 (answered by josgarithmetic)
Find all real numbers in the interval [0, 2pi) that satisfy each equation.
1.... (answered by lwsshak3)
sin (2x) = cos (2x) between (0,... (answered by Alan3354)