SOLUTION: Please help me with this problem: Let R be the region bounded by the x axis and the graph of y = tan x on the closed interval [0, pi/4]. Use the "disk method" to find the volume o

Question 1029854: Please help me with this problem:
Let R be the region bounded by the x axis and the graph of y = tan x on the closed interval [0, pi/4]. Use the "disk method" to find the volume of the solid formed when R is revolved about the x axis. Evaluate the integral.
Answer by Natolino1983(23) (Show Source): You can put this solution on YOUR website!
V=PI�INTREGAL FROM 0 to PI/4 (tg^2(x)dx).
Tg^2(x) = 1 - sec^2(x).
So the anti-derivative= x - tg(x).
So V = PI�( PI/4 -tg(pi/4) - (0 - tg(0)) =(Pi^2 -4�Pi)/4 cubic units.
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