SOLUTION: Suppose the weight of cereal in a box is labeled to contain 20 oz and is distributed with mean 20.1 oz. and standard deviation .2 oz. Y is the weight of cereal in a random box.

Question 1029720: Suppose the weight of cereal in a box is labeled to contain 20 oz and is distributed with mean 20.1 oz. and standard deviation .2 oz. Y is the weight of cereal in a random box.
How much do the heaviest 4% of boxes weigh?(calculate 96th percentile of distribution of Y)

Suppose that 300 samples are selected with a 95% confidence interval for the population mean. How many intervals are expected to contain the value of the population mean?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose the weight of cereal in a box is labeled to contain 20 oz and is distributed with mean 20.1 oz. and standard deviation .2 oz. Y is the weight of cereal in a random box.
How much do the heaviest 4% of boxes weigh?(calculate 96th percentile of distribution of Y)
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x = z*s + u
z = invNorm(0.96) = 1.7507
x = 1.7507*0.2 + 20.1
x = 20.45 oz
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Cheers,
Stan H.
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Suppose that 300 samples are selected with a 95% confidence interval for the population mean. How many intervals are expected to contain the value of the population mean?
Check you text book. This question is is testing your interpretation
of the meaning of a 95% confidence interval.
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