SOLUTION: I need some help with this problem: Differentiate: y = {{{lnx^2}}} + 1 + {{{e^(2x)/ (sec x + 1)}}}

SOLUTION: I need some help with this problem: Differentiate: y = {{{lnx^2}}} + 1 + {{{e^(2x)/ (sec x + 1)}}}

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Question 1024913: I need some help with this problem:
Differentiate: y = + 1 +
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let's do it in sections.

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Putting it all together,

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