SOLUTION: Please help me with this: Differentiate as many times as necessary in this problem: If s(x) = {{{1/sqrt(x) + 2sinx}}}, find s''(x).

Algebra ->  Test -> SOLUTION: Please help me with this: Differentiate as many times as necessary in this problem: If s(x) = {{{1/sqrt(x) + 2sinx}}}, find s''(x).      Log On


   

Question 1008975: Please help me with this:
Differentiate as many times as necessary in this problem:
If s(x) = 1%2Fsqrt%28x%29+%2B+2sinx, find s''(x).
Found 2 solutions by Boreal, Alan3354:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
s(x) =x^(-1/2)+2 sin x
s'(x)=-1/2(x^(-3/2))+2cosx
s''(x)=(3/4)x^(-5/2)-2 sin x

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If s(x) = 1%2Fsqrt%28x%29+%2B+2sinx, find s''(x).
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s(x) = x%5E%28-1%2F2%29+%2B+2sin%28x%29
s'(x) = %28-0.5%29%2Ax%5E-1.5+%2B+2cos%28x%29
s"(x) = %28-0.5%29%2A%28-1.5%29%2Ax%5E-2.5+-+2sin%28x%29
s"(x) = .75%2Ax%5E-2.5+-+2sin%28x%29