SOLUTION: Please help me solve this problem:
Show that the expression for the slope of the secant line through y=x^2 +3x at x=3 and x=3+h is msec=9+h.
Sketch the graph of y=x^2 +3x sh
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Question 1005325: Please help me solve this problem:
Show that the expression for the slope of the secant line through y=x^2 +3x at x=3 and x=3+h is msec=9+h.
Sketch the graph of y=x^2 +3x showing a sequence of secant lines described in the previous question as h approaches 0.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
The function is .
The secant requested is the straight line that passes through points
with and
with
The slope of secant is
--> --> --> -->
The graph with the secants for h=1, h=2, and h=3 are shown below.
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