SOLUTION: Please help me with this problem: Find the distance between the focus and vertex of the parabola whose equation is {{{y^2 = 8x}}}.

Question 1002658: Please help me with this problem:
Find the distance between the focus and vertex of the parabola whose equation is .
Found 2 solutions by MathLover1, Boreal:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

variable is one you'll need because it represents the distance between the vertex and the focus
you have sideways parabola and its equation is:

from given, we know that and ; so the vertex is at (,)
=> compare to , you see =>
then the distance between the vertex and the focus is and the focus is at (,)

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
y^2=8x is a horizontal parabola.
4p(x-h)=(y-k)^2
4p=8,
p=2
focus is 2 units to the right of the vertex, which is (0,0)

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