SOLUTION: x varies jointly with y and the cube of z and inversely with w. The value of x is 64 when y = 2, z = 4 and w = 6. Find x when y = 1, w = 15 and z = 3.

Question 1000413: x varies jointly with y and the cube of z and inversely with w. The value of x is 64 when y = 2, z = 4 and w = 6. Find x when y = 1, w = 15 and z = 3.

Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
x varies jointly with y and the cube of z and inversely with w
X = kYZ^3/W
k = constant of proportionality
Find 'k'
X = kYZ^3/W
64 = k24^3/6
k = (64 x 6)/(2 x 64)
k = 3
Formula:
X = 3YZ^3/W
...........
X = (3 x 1 x 3^3)/15
X = 5.4
Hope this helps. :-)
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