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put this solution on YOUR website!If ellen and sue leave school for the library at 3pm.
Ellen is going 12 miles per hour n sue is going 9 miles an hour.
Ellen gets there 15 mins before sue.
What time does ellen get there.
How far is the library
:
Change 15 min to .25 hr
:
Let d = distance to the library
:
Write a time equation; time = dist/speed
:
Sue's time - Ellen's time = 15 min
-
= .25
Multiply both sides by 36, results:
4d - 3d = .25(36)
d = 9 mi is the distance to the library
:
Find Ellen's time to get to the library
=
hr which is 45 min
3:00 + :45 = 3:45 time when Ellen get's there
