SOLUTION: a man's age is 3 times the sum of the ages of his two sons.after 5years his age will be twice the sum of the ages of his two sons.find the age of the man.
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Question 331524: a man's age is 3 times the sum of the ages of his two sons.after 5years his age will be twice the sum of the ages of his two sons.find the age of the man. Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! let age of sons be x & y & father's age =z
z = 3(x+y)
z/3 = (x+y)
..
after 5 years
their ages will be
x+5, y+5, z+5
z+5=2(x+5+y+5)
z+5=2x+2y+20
z+5=2(x+y)+20
z+5-20=2(x+y)+20-20
z-15=2(x+y)
But (x+y)= z/3
z-15=2*z/3
multiply 3
3*(z-15)=2z
3z-45=2z
3z-2z=45
z=45 father's age
