SOLUTION: a bricklayer measured the length of his wall to be 4.10m, if the actual length is 4.25m, what is his percentage error
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Question 982906: a bricklayer measured the length of his wall to be 4.10m, if the actual length is 4.25m, what is his percentage error
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Error=((Actual-Measured)/Actual)*100
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3.5%
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