SOLUTION: A poster advertising a student election candidate is too large according to the election rules. The candidate is told she must reduce the length and width of the poster by 20%. By
Algebra.Com
Question 780126: A poster advertising a student election candidate is too large according to the election rules. The candidate is told she must reduce the length and width of the poster by 20%. By what percentage must the area of the poster be reduced?
The answer is 36%, I just do not know how to get there.
Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!
A poster advertising a student election candidate is too large according to the election rules. The candidate is told she must reduce the length and width of the poster by 20%. By what percentage must the area of the poster be reduced?
The answer is 36%, I just do not know how to get there.
Let the length and width of the "too large" poster be L and W, respectively
Then its area = LW
Reducing its length, or L by 20% makes it 80% of its original length, or .8L
Reducing its width, or W by 20% makes it 80% of its original width, or .8W
New area with new, reduced length and width = .8L * .8W, or .64LW
It's obvious that the original area (LW) has been reduced to .64LW, which is a difference of LW - .64LW, or .36LW, or % of LW (area).
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